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3 years ago

9

If a yard of fabric cost $12.99 then how much will 2 feet cost

1 answer:

Ratling [72]3 years ago

5 0

We know that 1 ft= 1/3 yd.

2 ft* (1/3 yd/ 1 ft)* ($12.99/ 1 yd)= $8.66
(Note that the units cancel out so you get the answer)

2 ft of fabric will cost $8.66~

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Find the missing side of the triangle. Round your answer to the nearest tenth if necessary.

Soloha48 [4]

Answer:

Step-by-step explanation:

pythagoras theorem

a^2+b^2=c^2

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

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3 years ago

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Nesterboy [21]

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3 years ago

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Allisa [31]

Lyndon should spend $38.05 or more to get a free T-shirt.

We have to find the statement best represents all of the amounts he can spend to get a free T-shirt

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To find the value of x,

Solve above inequality

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Therefore,

Lyndon should spend $38.05 or more to get a free T-shirt

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3 years ago

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jekas [21]

Answer:

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Use the process of elimination to find out the y and plug the y in to get the x.

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