Answer:
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Answer:
Step-by-step explanation:
3 Great Ways to Teach Adding Integers
Typically, you should begin by having your students think about real world examples of positive and negative integer. ...
Then, model this example using counter chips.
Finally, have your students model addition problems using the counter chips.
I also agree that the answers is the second one have a beautiful day:)
Answer:
![(x + 7) * (3x + 1) = (3x^2 + 22x + 7)](https://tex.z-dn.net/?f=%28x%20%2B%207%29%20%2A%20%283x%20%2B%201%29%20%3D%20%283x%5E2%20%2B%2022x%20%2B%207%29)
Step-by-step explanation:
Given
![(3x^2 + 22x + 7) \div (x + 7) = 3x + 1](https://tex.z-dn.net/?f=%283x%5E2%20%2B%2022x%20%2B%207%29%20%5Cdiv%20%28x%20%2B%207%29%20%3D%203x%20%2B%201)
![(x + 7) * (\ ) = [\ ]](https://tex.z-dn.net/?f=%28x%20%2B%207%29%20%2A%20%28%5C%20%29%20%3D%20%5B%5C%20%5D)
Required
Complete the blanks
We have:
![(3x^2 + 22x + 7) \div (x + 7) = 3x + 1](https://tex.z-dn.net/?f=%283x%5E2%20%2B%2022x%20%2B%207%29%20%5Cdiv%20%28x%20%2B%207%29%20%3D%203x%20%2B%201)
Rewrite as:
![\frac{(3x^2 + 22x + 7) }{ (x + 7)} = 3x + 1](https://tex.z-dn.net/?f=%5Cfrac%7B%283x%5E2%20%2B%2022x%20%2B%207%29%20%7D%7B%20%28x%20%2B%207%29%7D%20%3D%203x%20%2B%201)
Cross multiply
![(x + 7) * (3x + 1) = (3x^2 + 22x + 7)](https://tex.z-dn.net/?f=%28x%20%2B%207%29%20%2A%20%283x%20%2B%201%29%20%3D%20%283x%5E2%20%2B%2022x%20%2B%207%29)