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Elza [17]
3 years ago
11

What statement is true

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer is d

-10+(-9)>3+(-25)


Because

-10-9 > 3-25

-19>-22

Veseljchak [2.6K]3 years ago
5 0
-10 + (-9) > 3 + (-25)
-19 > -22
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Answer: i THINK it might be c

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Express 0.24 as a percent
Hatshy [7]

Answer: 24%

Step-by-step explanation:

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2 and 5. What is the LCM?
Masja [62]
Well, first of all, LCM means Lowest Common Multiple. So you have to write out the factors of each of the numbers. So that will be;
2= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
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  So now, you have to pick out the numbers that are common to both numbers. So;
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5 0
3 years ago
625^x=5<br><br> A-1/4<br> B1/4<br> C-4<br> D4
murzikaleks [220]
Take logs of both sides:-

ln 625^x = ln 5

x * ln 0.625 = ln 5

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5 0
3 years ago
George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
3 years ago
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