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Rina8888 [55]
3 years ago
14

Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious

for me. Thank you.

Mathematics
1 answer:
docker41 [41]3 years ago
6 0

Answer:

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2

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Need the answer please 3 please answer
photoshop1234 [79]

Answer:

Positive 8

Step-by-step explanation:

The end value of -(-8) would be positive eight because when you multiply a negative by a negative, you get a positive value.

This question is essentially -1 times -8, which would equal 8

(The answer would be: 8)

I hope this helps!

7 0
3 years ago
Write 6 x 10 x 10 x 10 x 10 with an exponent
Travka [436]
I believe it would be 6(10^4)
3 0
3 years ago
Read 2 more answers
12-7(8*9)<br> 82<br>5-82<br>-77<br><img src="https://tex.z-dn.net/?f=12%20-%207%288x9%29%20%3D%20" id="TexFormula1" title="12 -
Goryan [66]

Well, that's incorrect because according to the Order of Operation [GEMS\BOMDAS\PEMDAS etc.], that -7 has to be distributed amongst all the other terms in parentheses. Besides, you did the wrong operation when you inserted that subtraction symbol in substitution of the parentheses, which means to MULTIPLY. So, the order goes as follows:

12 - 7[72]

-504 + 12 = -492 [OR 12 - 504]

-492 is your answer. You get it now?

3 0
3 years ago
Find the midpoint of the line segment with the given endpoints. R(-12, 8), S(6, 12)
umka21 [38]

Answer:

The answer is one.

Step-by-step explanation:

4 0
3 years ago
In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t
Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

(Y_1)^2 and (Y_2)^2 have x^2 distribution with 1 degree of freedom

and V=(Y_1^2)+(Y_2)^2 has x^2 with 2 degree of freedom

F_v(v)=\frac{e^{-\frac{v}{2}}}2

Since we have to find the density formula

U=\sqrt{V}

We use method of transformation

h(V)=\sqrt{U}\\\\=U

There inverse function is h^-^1(U)=U^2

We derivate the fuction above with respect to u

\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u

Therefore,

F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U

8 0
3 years ago
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