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kolbaska11 [484]
3 years ago
11

The diagram show a straight line ABC . Find the value of p

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0
Finding the change in y/change in x=the slope, we get
(13-11)/(-4-(-2))=2/-2=-1. Therefore, the equation is y=-1*x+b. Plugging it into (-4, 13), we note that 13=4+b and b=9 by subtracting 4 from both sides, making the equation y=-x+9. Plugging it into A, we get that
1 (y , the second value) = -x+9. Subtracting both sides by 9, we get 1-9=-x and -8=-x. Multiplying each side by -1, we get x=8
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Use substitution to slice this linear system<br><br> 3x-2y=6<br> 4y= -8
tatiyna
The answer to the question

8 0
3 years ago
Can you graph this equation - Y=3×^2
Vladimir [108]
So you start at 0 then (1,3) , (2,12) and the other side would be (-1,3) , (-2,12)
8 0
2 years ago
Read 2 more answers
Someone help me please
Black_prince [1.1K]

Answer:

C.

Step-by-step explanation:

Line CD has a slope of -5/3 and the negative reciprocal of 3/5. The slope for the line given is 3/5 so the slopes are right. Then look at the y-intercept of the line given: (0,-2)     Go up 3 and over 5 and you can see it pass through the line CD making C the answer.

5 0
3 years ago
PLEASE HELP, WILL MARK BRAINLIEST!<br><br> 7/9x +2 = 5/6
harina [27]

Answer:

Exact Form:

x= -3/2

Decimal Form:

x= -1.5

Mixed Number Form

x= -1 1/2

Step-by-step explanation:

4 0
3 years ago
The polynomial equation x5-16x2=4x4-64 has complex roots + or - 2i what are the other roots? use a graphing calculator and a sys
hichkok12 [17]

Kindly proofread the question!!!

The leading term is x^6, not x5.


Answer: The additional roots are -2, +2, each with multiplicity 2.


Step-by-step explanation:

x^6 - 16x^2 = 4x^4 - 64


x^6 - 4x^4 - 16x^2 + 64 = 0

(x+2i)(x-2i) = (x^2+4) is a factor.

(x-2)(x+2)(x-2)(x+2)(x^2+4) = 0

Polynomial long division by x^2+4

x^6 - 4x^4 - 16x^2 + 64 = 0

First term of quotient is x^4

Subtract x^6+4x^4

Remainder is -8x^4 -16x^2+64

Second quotient term is -8x^2

Subtract -8x^4-32x^2

Remainder is 16x^2+64

Third quotient term is 16

Subtract 16x^2+64

Remainder is zero

Quotient is x^4 - 8x^2 + 16

(x^2-4)^2 = x^4 + 2(1)(-4)x^2 + 16

(x-2)(x+2)(x-2)(x+2)(x^2+4) = 0


4 0
3 years ago
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