Answer:\frac{s-a}{n-1}
Step-by-step explanation:
formula, s=a+(n-1)d
1. get rid of the a on d's side by subtracting it from both sides.
s=a+(n-1)d becomes s-a=(n-1)d
2. get rid of (n-1) by dividing it from both sides. s-a=(n-1)d becomes
\frac{s-a}{n-1} =d
The answer is 9 just reciprocate the 1/3 and the multiply the 9 by 3
If I'm reading this correctly, it is 2*3*n*n = 6n^2
6n^2 = 54 Divide by 6
n^2 = 54/6
n^2 = 9 Take the square root of both sides.
sqrt(n^2) = sqrt(9)
n = +/- 3
n = + 3 or n = -3. Both will solve the equation above.
Edit
2 * 3 * n * n
Let n = 3
2 * 3 * 3 * 3 = 6 * 9 = 54
The other value is n = - 2
2 * 3 * n * n
2 * 3 * (-3) * (-3) A minus times a minus is a plus.
2 * 3 * 9 = 6 * 9 = 54
both + 3 and - 3 for n will give 54.
Answer: -4
Step-by-step explanation:
The outcome is negative since -16 is bigger than 12.
If you do the math then you will get -4
