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Alexandra [31]
3 years ago
6

What is the rational number between -2/3 and -5/6

Mathematics
1 answer:
hoa [83]3 years ago
7 0
Looks tuffff ^|^|~*~\^]+|*~
You might be interested in
A car uses 1 gallon of gasoline for every 25 miles driven. At the start of a trip the tank was full of gasoline. After driving 5
dezoksy [38]

Answer:

d = 22 - x / 25

Step-by-step explanation:

The first thing is to calculate the tank capacity, we know that per gallon 25 miles are traveled and at 500 miles there were still two gallons, therefore:

500 miles / 25 miles / gallon = 20

and how there were still 2

20 + 2 = 22

the tank has a 22 gallon capacity

Therefore the equation would be:

d = 22 - x / 25

where x is the number of miles traveled.

for example, if they have traveled 500 miles it would be:

d = 22 - 500/25 = 22 - 20

d = 2 gallons

we can verify that it is correct because it is what the statement says

8 0
3 years ago
Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
Can someone please help me with this?
ddd [48]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
75,575 - How do the values of the digits 5 differ in the number
nirvana33 [79]
The place value of a certain digit is 10 times bigger than its adjacent digit to the right so the compare to the 5 in the thousands place it is 1000 times bigger than the 5 in the ones place and 10 times bigger than the 5 in the hundreds place
3 0
3 years ago
Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq
AnnyKZ [126]

Answer:

(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the function

                    f(x) = e^{4x} \sqrt{1+e^{2x} }

Now integrating on both sides, we get

                 \int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx

                               =    \int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx

                         

<u><em>Step(ii):-</em></u>

  Let  1 + e^{2x}  = t

           e^{2x}  = t -1  

          2e^{2x}dx = d t

          e^{2x}dx = \frac{1}{2} d t

                = \int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx

                  = \int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }

                 = \frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }

                = \frac{1}{2} \int\limits {(t^{\frac{1}{2}  } t^{1} +t^{\frac{1}{2} } ) } \, dx

                = \frac{1}{2} \int\limits {(t^{\frac{3}{2}  } +t^{\frac{1}{2} } ) } \, dx

               = \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C

              =  \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C

             = \frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C

            = (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

<u><em>Final answer:-</em></u>

= (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

             

3 0
3 years ago
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