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rosijanka [135]
3 years ago
5

Solve 2 (3d + 3) = 7 + 6d.

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0

Simplify and multiply:

6d+6=7+6d

Subtract 6 from both sides:

6d=1+6d

Subtract 6d from both sides:

If you do this it isn't possible

So, your answer is no solutions.


Leni [432]3 years ago
4 0

First distribute in the 2 on the left side to get 6d+6=7+6d

Then, you would combine the variables to be on one side of the equation by doing -6d. However, this would cancel out the d by leaving you with 0d+6=7. That is the same thing as saying 6=7.

The answer to this equation is no solution because 6 is NOT equal to 7.

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Need help on these trig homework
allochka39001 [22]

8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 20 = \frac{x}{23}

Cross multiply

sin 20 × 23 = x

x = 0. 3420 × 23

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

sin 37. 3 = \frac{x}{19}

cross multiply

x = 0. 6059 × 19

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}

For side a, we use the Pythagorean theorem

c^2 = a^2 + b^2

85^2 = a^2 + 67^2

a = \sqrt{89^2-67^2}

a = \sqrt{3432}

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

\frac{59}{sin A } = \frac{85}{sin 90}

cross multiply

sin A × 85 = sin 90 × 59

make sin A subject of formula

sin A = \frac{59}{85}

sin A = 0. 6941

A = sin^-^1(0. 6941)

A = 44°

\frac{67}{sin B} = \frac{85}{sin 90}

cross multiply

sin B × 85 = sin 90 × 67

make sin b subject of formula

sin B = \frac{67}{85}

sin B = 0. 7882

B = sin^-^1( 0. 7882)

B = 52°

4. To find the sides, we use the sine rule;

\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}

Cross multiply

sin 56. 6 × c = sin 90 × 74

make 'c' subject of formula

c = \frac{74}{0. 8348}

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

c^2 = a^2 + b^2

b^2 = c^2 - a^2

b^2 = 88. 8^2 - 74^2

b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}

b = 49. 1 m

\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}

cross multiply

sin B = \frac{40. 99}{74. 0}

B = sin^-^1(0. 5539)

B = 34°

Learn more about trigonometric identity here:

brainly.com/question/7331447

#SPJ1

3 0
1 year ago
A company produces and sells CDs. There is a fixed cost of $2000 and $5 per CD manufactured. The manufacturer sells each CD for
OlgaM077 [116]
Call the production cost 'C', the revenue 'R' and the number of CDs 'n': 

C=2000+5n
R=10n
By definition Profit P = R-C, therefore P=10n-2000+5n = 5n-2000. 
7 0
3 years ago
a rectangular pool is 20 ft wide and 50 ft long. the deck is the same width all the way around the pool. the total area of the d
Alex
First, we need to get the total area of the rectangular pool.
Area = l * w
Area = 20 ft * 50 ft
Area = 1000 ft^2

Then the deck is 456 ft^2 with the width of 20ft, the same as the rectangular pool.

Area = l * w
456 = l * 20
l = 456 / 20
l = 22.8 ft.

So the walkway is 22.8ft wide.
3 0
3 years ago
GEOMETRY! The diagram shows 5 ft student standing near a tree. The shadow of the student and the shadow of the tree end at point
yuradex [85]

Answer: 24.99 ft

Step-by-step explanation:

1. You can find the angle A as following:

A=arctan(\frac{5}{8})\\A=32\°

2. Now, you can calculate the height of the tree as following:

tan(A)=\frac{opposite}{adjacent}

Where:

A=32°

opposite=x

adjacent=40

3. When you substitute values and solve for x, you obtain that the height of the tree in feet is:

tan(A)=\frac{x}{40}\\x=40*tan(32\°)\\x=24.99

8 0
3 years ago
What is the common ratio of the geometric sequence? 118, 13, 2, 12, 72, ... answers 12 .....1/6......60......6
AnnyKZ [126]
There is no answer to this in Geometric Sequence. Please check the question and type it again. I am not writing this to gain points, I already have a lot, but to let you know that there is no sequence for this question.

Hope it's clear to you:)
3 0
3 years ago
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