Answer:
hope it helps. if not just inform me. I'll try again.
Answer:
1) 120
2) E (Z) = 12 and Variance of Z = 90
a) 5 liters
Step-by-step explanation:
1. We can find this by suing combinations.
Here n= 10 and r= 3 so n C r
= 10 C 3= 120
2. E(X) = 8 and E(Y) = 3
Z = 2X - 3Y +5
E(Z ) = 2 E (X) - 3(E)(Y) +5 ( applying property for mean)
= 2(8) - 3(3)+ 5 = 16+5-9= 21-9= 12
V(X) = 9 and V(Y) = 6.
V(Z) = E(Z )²- V(X) *V(Y) (applying property for Variance for two variables )
= 144- 54= 90
3. 55 liters contain adulterated milk in 7: 4.
So it contains 4/ 11*55= 20 liters of water
But we want to make it a ratio of 7:6
the water will be 6/13 *55= 25.38 when rounded gives 25 liters of water
So 25- 20 = 5 liters must be added to make it a ratio of 7:6
Answer:
4.78 pounds
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 9.2 pound
σ is the population standard deviation = 3.4 pounds
z = 1.3
We are to find x
Hence,
-1.3 = x - 9.2/3.4
Cross Multiply
-1.3 × 3.4 = x - 9.2
-4.42 = x - 9.2
x = -4.42 + 9.2
x = 4.78 pounds.
Therefore the weight of the cat is 4.78 pounds
(y+1)=3(x-1) is the answer to your problem
ANSWER: V^2
Because there are 2V’s therefore it is v^2/v to the second power