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4 years ago

Find angle O A. 49 B. 59 C. 63 D. 78

Mathematics

2 answers:

Alisiya [41]4 years ago

8 0

<u>Answer:</u>

The correct answer option is A. 49.

<u>Step-by-step explanation:</u>

We know the length of the two sides: OP = 4 and PQ = 4.

Since two of the sides in the triangle are same, it is an isosceles triangle.

So, according to the properties of an isosceles triangle, the angles which are opposite to the sides with same length are also equal, therefore the angle OR is also equal to 49 degrees.

Free_Kalibri [48]4 years ago

6 0

Answer:

Step-by-step explanation:

In a triangle, if two sides are congruent, then their opposite angles are congruent.

OP = QP; therefore, m<Q = m<O.

m<O = m<Q = 49 deg

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003 divided by 6.321

ziro4ka [17]

0.47460844803037 this is the answer

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4 years ago

Find the inverse function answer to the question in the image attached.

koban [17]

The inverse function is:

$g(x) = 27*x^3 - 4$

And g(2) = 212.

<h3>How to get the inverse function?</h3>

We need to find g(x) such that:

g(h(x)) = x.

We know that:

$h(x) = \frac{\sqrt[3]{x + 4} }{3}$

Then our function must be a cubic, multiplied by 3^3 = 27, and then subtracts 4, it is:

$g(x) = 27*x^3 - 4$

As you can see, if you evaluate in h(x), the outcome is x.

Now we can evaluate this in x = 2, we get:

$g(2) = 27*2^3 - 4 = 212$

The correct option is C.

If you want to learn more about inverses.

brainly.com/question/14391067

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4 0

2 years ago

he American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 45 w

Sonja [21]

Answer:

The 85% confidence interval is (0.2187, 0.2613).

Step-by-step explanation:

We have a large sample of size n = 830 Americans over 45. We have observed that 631 people don't smoke. Let p be the population proportion of Americans over 45 who smoke. An point estimate of p is $\hat{p} = 199/830 = 0.24$ and an estimate of the standard deviation of $\hat{p}$ is $\sqrt{\hat{p}(1-\hat{p})/n} = \sqrt{(0.24)(0.76)/830}$ = 0.0148. Therefore, because we have a large sample, the 85% confidence interval for the population proportion is given by $\hat{p}\pm z_{\alpha/2}\sqrt{\hat{p}(1-\hat{p})/n} = 0.24\pm z_{0.15/2}0.0148 = 0.24\pm z_{0.075}0.0148$ where $z_{0.075}$ is the 7.5th quantile of the standard normal distribution, i.e., -1.4395. Therefore the 85% confidence interval is $0.24\pm (1.4395)(0.0148)$ or equivalently (0.2187, 0.2613).