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Kitty [74]
3 years ago
14

Unit circle , finding the angle please help

Mathematics
1 answer:
katrin [286]3 years ago
4 0
It is 45 or choice B
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tickets at a particular movie theatre have different rates for adults and children. on a friday the theatre sold 4 adult tickets
maria [59]
Using elimination method. Using substitution will cause some fraction problems.

c- child tickets
a- adult tickets

4a + 7c = $83
5a + 6c = $90

multiply by -5

-20a - 35c = -$415
20a + 24c = $360

-11c= -$55
c = $5 child tickets

4a + 7(5)= $83

4a + 35 = $83

4a = $48

a= $12 adult tickets

4 0
3 years ago
The box plots below show the average daily temperatures in January and December for a U.S.
Marysya12 [62]

Answer:

The answer is C

Step-by-step explanation:

Took the test!

3 0
2 years ago
Need help.please on number one
professor190 [17]
The answer is 12 including both sides and angles.

When you cut a square piece of paper from one point to the opposite point it should make two triangles.

Thus each triangle has 3 sides and 3 angles so two triangles has 6 angles and 6 sides

So 12, sides and angles added together. 
3 0
3 years ago
Read 2 more answers
48 lbs. equals how many kilograms?
Dahasolnce [82]
Your answer is 21.7724<span>Kilograms</span>
4 0
3 years ago
Read 2 more answers
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
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