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Sphinxa [80]
4 years ago
9

What is subtraction?

Mathematics
2 answers:
Mazyrski [523]4 years ago
5 0
Wen you deduct an amount from something
Inessa05 [86]4 years ago
3 0
Subtraction is part of the early arithmetic. Subtraction pertains to the part of math that involves reducing a sum to a smaller amount. Take this as an example, 7-4=3.
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Help me ASAP plssssss
qaws [65]

Answer:

point r (2,-9)

Step-by-step explanation:

You move left one and down 4 from point c

5 0
3 years ago
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7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value
mina [271]

Answer:

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]±t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{n} }]

t_{n-1;1-\alpha /2} = t_{6;0.975}= 2.365

[1403±2.365*\frac{27}{\sqrt{7} }]

[1378.87;1427.13]

The margin of error is the semiamplitude of the interval and you can calculate it as:

d= \frac{Upbond-Lowbond}{2}= \frac{1427.13-1378.87}{2} = 24.13

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

4 0
3 years ago
Please i need help with this question asap
Nataliya [291]

Answer:

I'm pretty sure it's C

Step-by-step explanation:

5 0
2 years ago
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Please help ! Mark brainly !
timama [110]

it would be positive because the positive number is bigger than the negative number.

3 0
3 years ago
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In a study of the length of time that students require to earn bachelor’s degrees, 60 students are randomly selected and they ar
Alex787 [66]

Answer:    (4.24,\ 5.36 )

Step-by-step explanation:

The  confidence interval to estimate the population mean is given by :_

\overline{x}\ \pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 60 , the sample is a large sample (n>30), so we can apply z-test.

Sample mean = \overline{x}=4.8

Standard deviation : \sigma=2.2

Level of confidence:1-\alpha=0.95

\Rightarrow\ \alpha=0.05

Then, critical z-value =z_{\alpha/2}=1.96

Then, a 95% confidence interval estimate of the population mean will be

=4.8\ \pm\ (1.96)\dfrac{2.2}{\sqrt{60}}\\\\=4.8\pm0.56=(4.8-11.76, 4.8+11.76)=(4.24,\ 5.36 )

Hence, the  95% confidence interval to estimate the population mean = (4.24,\ 5.36 ).

7 0
3 years ago
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