Answer:
55
Step-by-step explanation:
Cross multiply
|JG| = 
|JG| = 35
Therefore |IG| = |JG| + |IJ|
|IG| = 35 + 20
|IG| = 55
Please mark me brainiest if correct.
The answer
for such a question, it is required to graph each function, the answer is
<span>f(x) =4/5(4/5 )^x
check the attached file for proof</span>
The shaded region is a triangle. Triangle area can be determined with formula
a = 1/2 × b × h
From the question, we know that the triangle consists of
base = 10 - 6 = 4 m
and the height is the dimension which is perpendicular to the base,
height = 6 m
Find the triangle area
a = 1/2 × b × h
a = 1/2 × 4 × 6
a = 1/2 × 24
a = 12
The area of the shaded region is 12 m²
1,009.479 just add themmmm
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
