Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
Answer:
The correct answer is 1,51%
Step-by-step explanation:
To get the probability equally likely of the first 6 examined that have a defective compressor, we use the following formula
P=# of possibilities that meet the condition / #of equally likely possibilities.
As there are multiple events , and all must be achieve, we multiply the probabilities.
P1=7 / 11
P2=6 / 10
P3=5 / 9
P4=4 / 8
P5=3 / 7
P6=2 / 6
P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515
P(x)=1,51%
Answer:
I think that the answer is A.
Answer:
1
Step-by-step explanation:
You said peter picked only one pepper
