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andre [41]
4 years ago
8

Please help on this I’m too dum

Mathematics
2 answers:
bezimeni [28]4 years ago
7 0
For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.





sammy [17]4 years ago
4 0

Answer:

For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given system of equation are

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Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

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y=(-4)

Let x=1

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2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

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The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

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3 years ago
What is the measure of 1,2, and 3
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Step-by-step explanation:

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Step-by-step explanation:

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I and D are not going straight through the middle

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Answer:

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Step-by-step explanation:

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Girls 2x

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