A frequency table of grades has five classes (a, b, c, d, f) with frequencies of 44, 1515, 1818, 66, and 11 respectively.
what are the relative frequencies of the five classes?
1 answer:
Refer to the histogram shown below.
Total frequency = 44 + 1515 + 1818 + 66 + 11 = 3454.
Calculate relative frequencies, to the nearest thousandth.
Class a:
44/3454 = 0.0127
Answer: 0.013
Class b:
1515/3454 = 0.4386
Answer: 0.439
Class c:
1818/3454 = 0.5263
Answer: 0.526
Class d:
66/3454 = 0.0191
Answer: 0.019
Class f:
11/3454 = 0.0032
Answer: 0.003
Total frequency = 44 + 1515 + 1818 + 66 + 11 = 3454.
Calculate relative frequencies, to the nearest thousandth.
Class a:
44/3454 = 0.0127
Answer: 0.013
Class b:
1515/3454 = 0.4386
Answer: 0.439
Class c:
1818/3454 = 0.5263
Answer: 0.526
Class d:
66/3454 = 0.0191
Answer: 0.019
Class f:
11/3454 = 0.0032
Answer: 0.003
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>The age of Sita = (x + 5) years.
And, the age of Gautam = x years.
Now,
5 years ago, the ratio of their ages was 3 : 2
Now by cross multiplying, we get,
3x = 2(x + 5)
3x = 2x + 10
3x - 2x = 10
<h3>x = 10 </h3>Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.
And, the age of Gautam = x = 10 years.
Now,
The present age of Sita = 15 + 5 = 20 years. (Answer)
And, the present age of Gautam = 10 + 5 = 15 years. (Answer)