Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
10°
Step-by-step explanation:
the sum of interior angles of triangle is 180°
so. 8x+x+90°=180°
9x=90°
x=10°
I think it is the first one
Answer: 3; 3; 5; 8; 13; 21; 34; 55.
Try this option:
Step-by-step explanation:
the sum of the previous terms is the next term:3+5=8; 5+8=13; 8+13=21, then
13+21=34 and 21+34=55.
