Pls help I’m so stuck

For circle H, JN = x, NK = 2, LN = 3, and NM = 6. Solve for x. circle H with chords JK and LM intersecting at N inside the circl

vredina [299]

Answer:

x=9

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$JN*NK=LN*NM$ ----> by intersecting chords theorem

substitute the given values

$(x)(2)=(3)(6)$

solve for x

$x=18/2\\x=9$

4 0

3 years ago

Read 2 more answers

Vector u has its initial point at (17, 5) and its terminal point at (9, -12). Vector v has its initial point at (12, 4) and its

Ratling [72]

$\bf \vec{u}~~ \begin{cases} (17,5)\\ (9,12) \end{cases}\implies \implies \stackrel{\textit{component form}}{} \\\\\\ \vec{v}~~ \begin{cases} (12,4)\\ (3,-2) \end{cases}\implies \implies \stackrel{\textit{component form}}{} \\\\[-0.35em] ~\dotfill$

$\bf 3\vec{u}\implies 3\implies \\\\\\ 2\vec{v}\implies 2\implies \\\\\\ 3\vec{u}-2\vec{v}\implies -\implies + \\\\\\ \implies \\\\[-0.35em] ~\dotfill\\\\ ||3\vec{u}-2\vec{v}||\implies ||||\implies \sqrt{(-16)^2+33^2} \\\\\\ \sqrt{1345}\implies 36.67$

3 0

3 years ago

The ranger of the function x2+2x-8is allá

allsm [11]

Answer:

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

As the function is

$x^{2} +2x-8$

As we know that domain is the set of input values for which the function is defined.

Therefore,

$\mathrm{Domain\:of\:}\:x^2+2x-8\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

And range is defined as:

The set of the dependent variable for which the function is defined.

As

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(-1,\:-9\right)$

$f\left(x\right)\ge \:-9$

Therefore,

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Keywords: graph, domain, range

Learn more about domain and range from brainly.com/question/13856645

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8 0

3 years ago

Please help me with this question, image attached.

Lorico [155]

Answer:

110 degrees.

Step-by-step explanation:

Angles 2 and 3 are supplementary, and angles 8 and 7 are supplementary.

Angles 3 and 7 are equal.

If angle 8 is equal to 70 degrees, angle 3 is equal to 110.

5 0

4 years ago

Read 2 more answers

I don't under stand what is wrong.

MAXImum [283]

Answer:

In the first step, there is an issue when distributing the -3 to the terms inside of the parentheses. When multiplying the -3 to the -5, you would get an answer of +15, not -15.

The full correct process is:

(4m + 9) - 3(2m - 5) = 4m + 9 - 6m + 15

= 4m - 6m + 9 + 15

= -2m + 24

4 0

2 years ago