If exactly one woman is to sit in one of the first 5 seats, then it means that 4 men completes the first 5 seats.
No of ways 4 men can be selected from 6 men = 6C4 = 15
No of ways 4 men can sit on 5 seats = 5P4 = 120
No of ways 1 woman can be selected fom 8 women = 8C1 = 8
No of ways 1 woman can sit on 5 seats = 5P1 = 5
No of ways <span>that exactly one woman is in one of the first 5 seats = 15 * 120 * 8 * 5 = 72,000
No of ways 14 people can be arranged in 14 seats = 14!
Probability that exactly one woman is in one of the first 5 seats = 72,000 / 14! = 0.0000008259 = 0.000083%
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I'm going to rewrite the equation assuming this is the correct form:
Answer:
35-17=3y
Step-by-step explanation:
3y+17=35
-17 -17
3y=35-17
40! / 30! = 40*39*38*37*36*35*34*33*32*31
dividing this by 10! 10*9*8*7*6*5*4*3*2*1
= 4*13*19*37*17*11*4*31
= 847,660,528
