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Maurinko [17]
3 years ago
7

For a constant function, the y-coordinate is __________ for every pair of points selected, so the average rate of change always

has a value equal to
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

In mathematics, a constant function is one defined in which a function whose output value (y) is the same for every value of the input variable (x). Therefore this means that whatever is the value for x, the value of y would always be the same. Hence we can say that the function is a straight horizontal line in a Cartesian plane.

Since the value of y does not change, and the average rate of change has the formula:

average rate of change = (y2 – y1) / (x2 – x1)

So y2 – y1 = 0 therefore average rate of change is also zero.

 

Hence to complete the sentence:

For a constant function, the y-coordinate is <u>the same</u> for every pair of points selected, so the average rate of change always has a value equal to <u>zero</u>.

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Sam has purchased collision insurance with a $100-deductible clause, and automobile medical payments insurance in the amount of
REY [17]

The amount that the insurance company will pay is $1800.

<h3>How to illustrate the information?</h3>

It should be noted that the insurance company will pay John for the expenses of his injuries and repair of the car.

For the injury, he will get:

= $500 + ($1400 - $100)

= $500 + $2300

= $1800

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3 0
2 years ago
The large rectangle was reduced to create the small rectangle.
Tema [17]

Answer:

The ratio must be guaranteed.

Therefore,

18/6 =12/x

=> x= 6*12/18 = 4

7 0
3 years ago
1. Which comparison is not correct? O 3.2 &gt; 15 30 &lt; 15 2 0 -- 17 &gt; - 22 0 3. can someone please help me.
Talja [164]

Answer:

15 30 is not correct hope i helped

Step-by-step explanation:

4 0
3 years ago
Find an equation of the tangent line to the curve at the given point. y = 3x3 - x2 + 2, (1, 4)
ICE Princess25 [194]

y = 7x - 3

Note the gradient of the tangent is the derivative of y at x = 1

Differentiate using the power rule

\frac{d}{dx}(ax^{n}) = nax^{n-1}

y = 3x³ - x² + 2

\frac{dy}{dx} = 9x² - 2x

x = 1 : \frac{dy}{dx} = 9 - 2 = 7 ← gradient of tangent

equation in point- slope form, using m = 7 and (a, b) = (1, 4)

y - 4 = 7(x - 1) ← point-slope form

y - 4 = 7x - 7

y = 7x - 3 ← in slope-intercept form



4 0
3 years ago
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}

a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

3 0
3 years ago
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