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il63 [147K]
3 years ago
14

Please help soon! Thanks! Solve for x

Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

x=30^{\circ}

Step-by-step explanation:

Looking at \triangle LMN:

\angle NML = 180 - (90+45) (angle sum of triangle is 180^{\circ})

=45^{\circ}

Looking at \triangle KNM:

\angle KNM = 180-105 (angle of straight is 180^{\circ})

=75^{\circ}

\angle KNM + \angle NKM + \angle KMN = 180 (angle sum of triangle is 180^{\circ)

75+2x+45 = 180

2x+120 = 180

2x=60

x=30^{\circ}

Hope this helps :)

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Answer:

25< or >75

Step-by-step explanation:

6 0
4 years ago
Help me plzz I don't get any of this!?
nignag [31]
1. 3x ≤ 9
Divide 3 on both sides.
3/3 = 1 9/3 = 3

x ≤ 1

Your line graph should have a little line like this: | and with the number 1 under it.
It will be a shaded in circle since it's greater than, less than, and you goes to infinite.

2. 4x - 3  ≥ 13
Add 3 to both sides

4x ≥ 16
divide 4 into both sides

x ≥ 4

3. 4x - 3 < 13

same thing as 2
add 3 onto both sides
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this one is a bit different when you are using a line graph, you are going to do a opened circle, do not shade it in and then draw back.

4. 5x + 10 > 14x - 8

add 8 onto both sides.

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subtract 5x.

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add 6 to both sides

2x < 8

divide by 2,

x < 4

6. 2x - 5 ≤ x - 2

add to onto both sides.

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4 0
3 years ago
Apply each of the transformations you found in Problem 1 to the points x = ????11
NikAS [45]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Round 1,400,304.7258 to the nearest hundred thousand
Jet001 [13]

Answer:

1,400,304.726 is the answer

4 0
3 years ago
PLE help ASAP!
koban [17]

Answer:

The time it would take the element to decay to 28 grams is approximately 22.5 minutes

Step-by-step explanation:

The give half life of element X = 6 minutes

The given initial mass of the radioactive element X = 390 grams

The mass of the element X after decay = 28 grams

The function that represent the decay of element X is given as follows here;

y = a \cdot (0.5)^{\dfrac{t}{h} }

Which is of the form;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

Therefore;

h = 6 minutes = The time duration of the half life

a = N₀ = The initial mass = 390 g

N(t) = The final mass = 28 g

t = The time it takes the element to decay

Plugging in the values gives;

28 = 390 \times(0.5)^{\dfrac{t}{6} }

(0.5)^{\dfrac{t}{6} } = \dfrac{28}{390}

Therefore;

\dfrac{t}{6} \times ln\left(0.5} \right) = ln \left(\dfrac{28}{390} \right)

t/6 = ln(29/390)/ln(0.5)

t = 6 ×  ln(29/390)/ln(0.5) ≈ 22.496

Given the answer to the nearest tenth of a minute, the time it would take the element to decay to 28 grams, t ≈ 22.5 minutes.

3 0
3 years ago
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