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3 years ago

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Jackson recorded the growth of a plant over 10 weeks. The equation y=0.25+4 represents the height y in inches over time x in wee

ks what does the y intercept represent In terms of the situation

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

Allow me to rewrite your question and hope it will fit the original one:

<em>Jackson recorded the growth of a plant over 10 weeks. The equation </em><em>y=0.25x+4</em><em> represents the height y in inches over time x in weeks what does the y intercept represent In terms of the situation</em>

My answer:

As we know that y intercept is the value of y at the point where the line crosses the y axis (the value of x =0)

So in this situation, if x= 0, it means the height of the tree (y-intercept) initially be at 4 at week 0.

Hope it will find you well.

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What is the slope of a line that passes through (-12,15) and (0,4)

pav-90 [236]

Answer:

D. -11/12

Step-by-step explanation:

7 0

3 years ago

I will give you 100 points if you can answer this<br><br> (66×578)÷3368=55÷77=???

erma4kov [3.2K]

(66✖️578) ➗ 3368=55➗77

P parentheses
E exponents
M multiplication
D division
A addition
S subtraction

You would do (66✖️578) first since it is in parentheses
66✖️578=38,148

38,138➗3368=55➗77
Since there are no exponents or multiplication you would do division

38,138➗3368= 11.3236342
55➗77=0.7

11.32 does not equal 0.7
So this equation would be false

Hope this helps! :3

3 0

3 years ago

Read 2 more answers

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago

LxWxH pls and thank u

lutik1710 [3]

l = 2in

b = h = 3in

now , Lbh

= 2×3×3

= 18 in³

i hope this helps

4 0

2 years ago

Factorise the following 27 x minus 9 y

dangina [55]

Answer:

27x-9y

3(9x-3y)

Step-by-step explanation:

please mark me as brainlest

4 0

2 years ago