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vagabundo [1.1K]
3 years ago
14

Lance says that you can compare any decimal numbers the way that you alphatbetize words you can tell which number is first by co

mparing each digit from left to right. Is lance thinking correct.
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

Step-by-step explanation:

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

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Answer:

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Step-by-step explanation:

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2 years ago
(a) An angle measures 43 . What is the measure of its complement? (b) An angle measures 81 . What is the measure of its suppleme
vampirchik [111]
To solve the problem shown above, you must follow the proccedure shown below:

 1. By definition, Completary angles are those angles whose sum is 90 degrees and Suplementary angles are those angles whose sum is 180 degrees.

2. Keeping the information above on mind, you have:
<span>
 (a) An angle measures 43 . What is the measure of its complement?

 =90°-43°
 =47°

 (b) An angle measures 81 . What is the measure of its supplement?
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7 0
3 years ago
Eugene took out a loan for $1075 at a 12.6% APR, compounded monthly, to
aleksandr82 [10.1K]

Answer:

approximately 12 payments.

Step-by-step explanation:

you can pay off the loan in a year by multiplying 87.25 and 12. this will give you 1047, which is about 28$ off. then after that year, you can pay off the $28 whenever you finish with the 87.25

5 0
3 years ago
Read 2 more answers
What are 2 common mistakes people make when using quotient rule with exponents?
NemiM [27]

Answer:

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2. Not subtracting the exponents of the denominator from the exponent of the numerator when applying the quotient rule.

5 0
1 year ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
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