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lianna [129]
3 years ago
11

Two hours after a truck leaves phoenix traveling 45 miles per hour, a car leaves to overtake the truck. if it takes the car ten

hours to catch the truck, what was the car's speed?
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

The correct answer is 54 miles per hour

Step-by-step explanation:

To solve this problem we have to use the formula of

Speed=Distance/time

Both, car an truck made the same distance,  so

Distance car=Speed car*time car

Distance truck =Speed truck*time truck  

Distance car=Distance truck

So Speed car*time car =Speed truck*time truck  

Speed car =Speed truck* time truck /time car

Time truck = time car +2 ( truck leaves 2 hours before)

Time car =10

Speed car =45 miles per hour* 12 /10

Speed car = 54 miles per hour

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Simplify this following question:
Savatey [412]
I hope this helps you

5 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs.
Mashcka [7]

Answer:

Part 1) -17\frac{8}{9} -----> -6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

Part 2) -15.11 ------> -12.48-(-2.99)-5.62

Part 3) -19\frac{8}{9} -----> -19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

Part 4) -201.65 -----> -353.92-(-283.56)-131.29

Part 5) 74 ------> 83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

Step-by-step explanation:

Part 1) we have

-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

To calculate the subtraction convert the mixed numbers to an improper fractions

6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}

3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}

8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}

substitute

-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}

Convert to mixed number

-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}

Part 2) we have

-12.48-(-2.99)-5.62

To calculate the subtraction eliminate the parenthesis first

-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11

Part 3) we have

-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

To calculate the subtraction convert the mixed numbers to an improper fractions

19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}

4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}

3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}

substitute

-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})

Eliminate the parenthesis

-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}

Convert to mixed number

-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}

Part 4) we have

-353.92-(-283.56)-131.29

To calculate the subtraction eliminate the parenthesis first

-353.92+283.56-131.29=-201.65

Part 5) we have

83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

To calculate the subtraction convert the mixed numbers to an improper fractions

83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}

108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}

99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}

substitute

\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})

Eliminate the parenthesis

\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74

3 0
3 years ago
Please help me <br> 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2)<br><br> Simplify
I am Lyosha [343]

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

[3(x+2)*10*7]÷70 - 2(x+2)

= 3(x+2)*70÷70 - 2(x+2)

= 210(x+2)/70-2x-4

= 210(x+2)/66-2x

= 210(x+2)/2(33-x)

= 105(x+2)/33-x

8 0
3 years ago
Which expression is equivalent to 3x/x+1 divided by x + 1?
kiruha [24]
I hope this helps you.

7 0
3 years ago
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Additive inverse of −2, additive identity of −5, additive inverse of 3, multiplicative identity of 19, and multiplicative invers
monitta

Answer:

See Explanation

Step-by-step explanation:

a) Additive inverse of −2

  • the additive inverse of a number a is the number that, when added to 'a', yields zero. This number is also known as the opposite (number), sign change, and negation.
  • So the Additive inverse of -2 is 2. ∴ -2+2=0

b) Additive identity of −5

  • Additive identity is the value when added to a number, results in the original number. When we add 0 to any real number, we get the same real number.
  • -5 + 0 = -5. Therefore, 0 is the additive identity of any real number.

c) additive inverse of 3

  • Two numbers are additive inverses if they add to give a sum of zero. 3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.

d). multiplicative identity of 19

  • an identity element (such as 1 in the group of rational numbers without 0) that in a given mathematical system leaves unchanged any element by which it is multiplied
  • Multiplicative identity if 19 is 1 only, since 19 x 1 = 19.

e) multiplicative inverse of 7

  • Dividing by a number is equivalent to multiplying by the reciprocal of the number. Thus, 7 ÷7=7 × 1⁄7 =1. Here, 1⁄7 is called the multiplicative inverse of 7.

d)  | 11-5|×|1-5|

  • | 11-5|×|1-5| ⇒ I6I×I-4I ⇒ 6×4 ⇒ 24

8 0
3 years ago
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