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3 years ago

11

What is the slope of the line of (6,22) and (15,55) please simplify

1 answer:

Dennis_Churaev [7]3 years ago

5 0

Answer:

11/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(55-22)/(15-6)

m=33/9

simplify

m=11/3

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What is the length of ST¯¯¯¯¯? Enter your answer as a decimal in the box. Round your final answer to the nearest hundredth. in.

allochka39001 [22]

Answer:

_ST = TQ-TR (23-7)

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2 years ago

Read 2 more answers

During her summer vacation, Samantha worked at an insurance company for eleven weeks. She earned a total of $3,960. She did not

SVEN [57.7K]

Answer: <em>She earned $72 per day. </em>

<em>The computation that will give Samantha's daily pay is: $\frac{\$3960}{5\times 11}$ </em>

Step-by-step explanation:

Samantha did not work on weekends. That means, <u>she worked for 5 days in a week</u>.

Given that, she worked at the insurance company for 11 weeks. So, <u>the total number of her working days</u> $=(5\times 11)= 55$

She earned a total of $3,960.

So, the amount she earned daily $=\frac{\$3960}{55}=\$72$

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3 years ago

This is equations and graph. Please answer correctly :(

miss Akunina [59]

1. y= -x + 3

2. y = x - 3

3. y = 3x + 1

4. y = -3x - 3

7 0

2 years ago

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

$k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8$

we get

$k+1=-8\quad$

$k=-9$

$k+1=8\quad$

$k=7$

so,

$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

5 0

3 years ago

Help on 2 pleeeeeaaassseee

Anastasy [175]

10^9 (Ten to the power of nine)

5 0

3 years ago