Question

Suppose that E and F are two events and that Upper N (Upper E and Upper F )N(E and F)equals=250250 and Upper N (Upper E )N(E)equals=560560. What is Upper P (F|E )P(F|E)​?

Answer 1

Answer:

the probability is 0.4642 (46.42%)

Step-by-step explanation:

for the events E and F such that

N(E ∩ F) = 250 and N(E) = 560

where N represents the number of elements in that set , we can use the theorem of Bayes for conditional probability .Then representing  N total =N(E∪F) , we have that the probability is

P( F|E ) = P (E ∩ F)/ P(E) = [N(E ∩ F) / N total]/ [N(E) / N total ] = N(E ∩ F)/ N(E) =  250/560 = 0.4642 (46.42%)