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miskamm [114]
2 years ago
12

Indicate the equation of the given line in standard form. Write the answer in the equation box below.

Mathematics
1 answer:
denis-greek [22]2 years ago
5 0

Answer:

x + 8y - 35 = 0.

Step-by-step explanation:

The hypotenuse is the line joining A and C.

Slope = (4-5) / (3 + 5)

= -1/8.

Equation is:

y - 4 = -1/8(x - 3)

y - 4 = -1/8x + 3/8

1/8x + y - 35/8 = 0

x + 8y - 35 = 0

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Answer:

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Step-by-step explanation:

All you have to do is plug in the # under the letter x , and plug it into the equation. For example 18 - 3 x 1 , is just saying what is 18 - 3 . Another example would be 18 - 3 x 2 . the equation is simply just 18 - 6 . Just plug in the x numbers in the equation. Hope my answer helped  , and good luck! : )

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2 years ago
Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
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