476.00×5%=23.80 tax=476+23.80=499.80
499.80×15%=74.97
499.80+74.97=574.77
Answer:

Step-by-step explanation:
Given


Required
Determine the difference
Represent this with d.
d is calculated using

The equation becomes

Answer:
The population in 40 years will be 1220.
Step-by-step explanation:
The population of a town grows at a rate proportional to the population present at time t.
This means that:

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.
The initial population of 500 increases by 25% in 10 years.
This means that 
We apply this to the equation and find t.




Applying ln to both sides




So

What will be the population in 40 years
This is P(40).


The population in 40 years will be 1220.
3.341 to the nearest tenth is 3.3
You should ask your parent/guardian
or teacher if needed! Merry Christmas!