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stepan [7]
3 years ago
15

Need some help please

Mathematics
2 answers:
dalvyx [7]3 years ago
6 0

Answer:


Step-by-step explanation:


Gnoma [55]3 years ago
3 0
You can use this to help you. label the triangle like the picture and use the equations. I hope this helps.

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Step-by-step explanation:

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F=fg/f+g-d Solve for f. F and f are different!
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For which regular polygon is 30 degrees the smallest angle of rotational symmetry?
eduard
<h3>answer.</h3>

•given that is smallest angle of rotational symmetry for a regular polygon is 30

•we have to find the number of side does the regular polygon have

•if we can rotate of figure around a center point be fewer than 360° and the figure appears and change then the figure has the rotation symmetry

<h3>Hence,12 number of sides the polygon.</h3>

no. of side= 360/ smallest angle at centre=12

<em>I hope</em><em> </em><em>it's </em><em>help</em>

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What is wrong with the following equation?x2+x−20/x−4=x+5a. (x−4)(x−5)≠x2+x−20b. The left-hand side is not defined f
joja [24]

Answer:

The answer to this question can be defined as follows:

In part (i), the answer is "option d".

In part (ii), the answer is "option 2".

Step-by-step explanation:

Given:

Part (a)

\Rightarrow \bold{\frac{x^2+x-20}{x-4}=x+5}\\\\

Solve  the above equation:

\Rightarrow x^2+x-20=(x+5)(x-4)\\\\\Rightarrow x^2+x-20=(x^2-4x+5x-20)\\\\\Rightarrow x^2+x-20=x^2-4x+5x-20\\\\\Rightarrow \boxed{x^2+x-20=x^2+x-20}\\

Given:

Part (b)

\Rightarrow \bold{ \lim_{x \to \3} \frac{x^2+x-12}{x-3}= \lim_{x \to 3} (x+4)}\\\\

Solve the above equation:

factor of \Rightarrow x^2+x-20 =(x-3)(x+4)

\Rightarrow  \lim_{x \to \3} \frac{(x-3)(x+4)}{x-3}= \lim_{x \to 3} (x+4)\\\\\Rightarrow  \lim_{x \to \3} (x+4)= \lim_{x \to 3} (x+4)\\\\

apply limit value:

\Rightarrow  (3+4)=  (3+4)\\\\\Rightarrow  7= 7

6 0
3 years ago
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