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Rashid [163]
3 years ago
11

Roselyn is a college student with two part-time jobs. She works a few hours a day at the college laboratory, which pays her at a

rate of $8 per hour. She also makes small pendants that she sells for $4 a piece. She needs to earn at least $160 a week to cover her expenses.
If Roselyn sold 10 pendants in a week, then she must have worked at least ?
hours at the laboratory to cover her weekly expenses
Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

15 hours.

Step-by-step explanation:

We first need to see how much money Rose would earn if she sold the 10 pendents, so we will multiply 4×10.

4×10=40

Now we know, she already has 40 dollars of the 160 dollars she needs.

To find out how much she needs left, we will subtract 40 from 160.

160-40=120

She needs a total of 120 more dollars from working.

To find out how many hours she needs to work, we will divide 120 by 8.

120÷8=15.

In conclusion, she needs to work for at least15 hours to receive enough money.Please help me by marking this brainliest, and giving a thanks!

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Answer:

Step-by-step explanation:

7 0
3 years ago
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What is the solution of -8 / 2 y - 8 equals 5 / y + 4 - 7 y + 8 / Y 2 - 16​
AysviL [449]

Answer:

The value of y is 6.

Step-by-step explanation:

The given equation is

\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}

It can be rewritten as

\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}+\dfrac{7y+8}{y^2-4^2}

\dfrac{-4}{(y-4)}=\dfrac{5}{y+4}+\dfrac{7y+8}{(y+4)(y-4)}

Multiply both sides by (y+4)(y-4).

(y+4)(y-4)(\dfrac{-4}{(y-4)})=(y+4)(y-4)(\dfrac{5}{y+4})+(y+4)(y-4)(\dfrac{7y+8}{(y+4)(y-4)})

(y+4)(-4)=(y-4)(5)+7y+8

-4y-16=5y-20-(7y+8)

-4y-16=5y-20-7y-8

-4y-16=-2y-28

-4y+2y=-28+16

-2y=-12

Divide both sides by -2.

y=6

Therefore, the value of y is 6.

5 0
3 years ago
Three students made fruit punch to serve at the school carnival.
julsineya [31]

Answer:

136 GLASSES

Step-by-step explanation:

THERE ARE 40 CUPS IN 2.5 GALLONS

THERE ARE 36 CUPS IN 2.25 GALLONS

THERE ARE 60 CUPS IN 3.75 GALLONS

SO  {40+60=100

100+36=136

5 0
3 years ago
A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:
marin [14]

Answer:

Range = 85

\sigma = 28.71

Interval = [666.78, 781.62]

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

Range = Highest - Least

From the dataset:

Highest = 772

Least = 687

So:

Range = Highest - Least

Range = 772-687

Range = 85

The standard deviation is:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}

First, calculate the mean

\bar x = \frac{769 +691 +............+715}{25}

\bar x = \frac{18105}{25}

\bar x = 724.2

So, the standard deviation is:

\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}

\sigma = \sqrt{\frac{20604}{25}}

\sigma = \sqrt{824.16}

\sigma = 28.71

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]

Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]

Interval = [666.78, 781.62]

4 0
3 years ago
Which is the biggest number 2.07 2.24 2.4 2 2.04
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4 years ago
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