Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
34.99°
Step-by-step explanation:
CHECK THE ATTACHMENT FOR THE FIQURE
Let angle( X) = angle if elevation
From trigonometry, tan(X)= opposite/ adjacent
Height of the flagpole= 21 ft , which is the opposite side
The base, adjacent side = 30 ft
If we substitute the values we have
Tan(X) = 21/30
Tan(X)= 0.7
Tan-1(0.7)=34.99°
Hence, the angle of elevation of the sun when this shadow will cast is 34.99°
the top part solve for x by simplifying both sides of the equation then isolating the variable.
x= -175
second part solve for x by simplifying both sides of the equation then isolating the variable ;
x = -175
third part:
x = -175
fourth part;solve for x by simplifying both sides of the equation then isolating the variable
x = -175
fifth part;
x= -175
sixth part;
nothing further can be done with this topic
so its
x= -175 :p
To answer this question, first calculate the z-score:
test score - mean score 65 - 70
z = ----------------------------------- = ------------------- = -5/10 = -0.5
std. dev. 10
We need to determine the area under the normal curve to the left of z = -0.5.
Refer to a table of z-scores, and look for z=-0.5. What area appears in connection with this z-score? It's less than 0.5000.
Using my TI-83 Plus calculator (specifically, its "normalcdf( " function, I found that the area under the std. normal curve to the left of z = -0.5 is 0.309.
Thus, the percentile is 30.9, or roughly 31 (31st percentile).
Roughly 31% of students earned a grade lower than 65, and roughly 69% earned a higher grade.
As a mixed number 3 29/100 or as an improper fraction 329/100