Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
Hope this helps!
Mark me as brainliest
The slopes of the relationships are given as follows:
6. 5.
7. 1.
<h3>What is the complete question?</h3>
The problem is incomplete, as the tables are not readable, but researching it on a search engine, we find that:
- For item 6, we have points (2,8) and (6,28).
- For item 7, we have points (-6,5) and (4,10).
<h3>How to find the slope of a line given two points?</h3>
Given two points in the format (x,y), the slope of the line is given by change in y divided by change in x.
Hence, the slopes for each problem are given as follows:
6. m = (28 - 8)/(6 - 2) = 20/4 = 5.
7. m = (10 - 5)/(4 - (-6)) = 10/10 = 1.
More can be learned about the slope of a line at brainly.com/question/24808124
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Answer:
$48.96
Step-by-step explanation:
Given data
Length= 10inches
Width=14 inches
Let us find the perimeter of the certificate
P=2L+2W
P= 2*10+2*14
P=20+28
P= 48 inches
Hence if 1 inche cost $1.02
Then 48 inches will cost x
cross multiply we
x= 48*1.02
x= $48.96
Hence it will cost $48.96 to frame the certificate
Answer:
it will float!
Step-by-step explanation:
in order to find density, you must divide the mass by the volume. the volume is 56 ml, and the mass is 45.5. (45.5 / 56 = 0.8125) because we know the density of water is 1, and the density of this liquid is less than that of water, it will float because it is "lighter". hope it helped <33
