Answer:
The correct option is C).
Figure show the line with slope of -1/2 and a y-intercept of 3
Step-by-step explanation:
The equation of line is given by y=mx+c.
Where m is slope and c is y-intercept.
Given that line has slope
m=
and c=3
Thus equation of line will be
y=mx+c.
y=![\frac{-1}{2}x+3](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7Dx%2B3)
To plot the line we need at least two points
Take x=0
y=![\frac{-1}{2}x+3](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7Dx%2B3)
y=![\frac{-1}{2}0+3](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D0%2B3)
y=3
The required point is A(0,4)
Take x=2
y=![\frac{-1}{2}2+3](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D2%2B3)
y=2
The required point is B(2,2)
Using this points to graph the given equation of line
Figure show the line with a slope of -1/2 and a y-intercept of 3
The correct option is C).
The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
Answer:
5/7
Step-by-step explanation:
A common factor of 8 can be canceled from numerator and denominator.
40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7
_____
Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.
__
If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...
56 ÷ 40 = 1 r 16
40 ÷ 16 = 2 r 8
16 ÷ 8 = 2 r 0 . . . . . the zero remainder signals that the divisor (8) is the GCD
Now, your fraction is ...
(40/8) / (56/8) = 5/7