Answer:
the graph that goes through the points
(0,3), (-4,0)
Step-by-step explanation:
make y the subject
3x-4y=-12
4y=3x+12
y=(3x+12)/4
now when x=0
y=12/4=3
so coordinates (0,3)
now when y=0
0=(3x+12)/4
by multplying both sides by 4
0=3x+12
0=3 (x+4)
divide both sides by 3
0=x+4
x=-4
so coordinates (-4,0)
Answer:
see explanation
Step-by-step explanation:
let pq = x
given oq - pq = 1 then oq = 1 + x
Using Pythagoras' identity, then
(oq)² = 7² + x²
(1 + x)² = 49 + x² ( expand left side )
1 + 2x + x² = 49 + x² ( subtract 1 from both sides )
2x + x² = 48 + x² ( subtract x² from both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ⇒ pq = 24
and oq = 1 + x = 1 + 24 = 25 ← hypotenuse
sinq = =
cosq = =
