Answer:
There are infinitely many solutions. Start with five data, in size order: a < b < c < d < e. Then c=11, the median. To get the mode of 12, we must have d=e=12. Thus far, we have (a+b+11+24)/5 = 10 the mean. But now we have run out of requirements, and we still have two unknowns. They satisfy a+b+35 = 50. Thus, pick any two values a not equal to b that add to 15 and are both less than 11.
The full set of solutions are points (a,b) run along a line joining the points (4,11) and (11,4) on graph paper, except (7.5, 7.5) and the endpoints. That would make competing modes. Try a=5.6 and b = 9.4 for instance!
The first one is right because the mean is the average so it has to be in between. Usually. Hoped this helped!
Answer:
The function f(x) has a vertical asymptote at x = 3
Step-by-step explanation:
We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.
For example, in the case of the natural logarithm, it is not defined for x = 0.
Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)
So a vertical asymptote will be a vertical tendency at a given x-value.
In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)
Then:
The function f(x) has a vertical asymptote at x = 3
Avg of 7 numbers = 9
Total of 7 numbers will be = 9 * 7 = 63
Avg of 3 of them is = 5
Total of those 3 will be = 3 * 5 = 15
Therefore the total of other 4 = 63 - 15 = 48
Ergo , avg of them = 48 / 4 = 12
Answer is 12
hope this helps!
