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djverab [1.8K]
3 years ago
5

If f(a) =11, then use the table above to find f(a-2)​

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

<h2>7</h2>

Step-by-step explanation:

From the table

f(a) = 11 → a = 7

a - 2 = 5

f(a - 2) = f(5) = 7

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6x – 2y = 10 2x + 3y = 51 solving the first equation above for y gives:
Masja [62]
The first equation is 6x - 2y = 10. To solve for y, you will use inverse (opposite) operations to undo what is happening to y.  Please see the steps below for the work.

6x - 2y = 10
-6x          -6x
<u>-2y </u>= <u>(-6x + 10)</u>
-2            -2
y = 3x - 5
6 0
3 years ago
Calculate the product of and 1/5 +2/9=
Phantasy [73]
\frac{1}{5}~+~ \frac{2}{9}

Find the same denominators

\frac{9}{45}~+~ \frac{10}{45}

\frac{9~+~10}{45}

\frac{19}{45}

Answer = \frac{19}{45}



5 0
4 years ago
Read 2 more answers
The table and the graph each show a different relationship between the same two variables, x and y:
Inessa05 [86]

Answer:

275

Step-by-step explanation:

3 0
2 years ago
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Olivia and her children went into a grocery store where they sell peaches for $2 each and mangos for $1 each. Olivia has $15 to
Naddik [55]
Here is an example of how to do it⬇️

Set variables for the quantities we want to find.

Let x = number of apples
Let y = number of oranges


Next, we use these variables to write equations that describes the whole story.

Since the total price is $7.75 and each type of fruit has their own price, we can say

0.40x + 0.35y = 7.55


The other equation will represent the total number of fruits bought all together, as Mark mentioned. Once you have those equations, you solve the system using substitution and elimination methods to solve for the variables x and y.

(If x represents the number of peaches purchased and y represents the number of mangos purchased)

Sorry if this isn’t good explanation but I tried sorry goodluck!
8 0
3 years ago
Jack likes to go fishing. While waiting for the fishes to bite, he formulates the following model for the process: fishes bite a
gogolik [260]

Answer:

a) 0.122

b) 3.35 × 10⁻⁴

c) 0.1071

Step-by-step explanation:

Here we have the Poisson process given by

P(N(t) = k) = \frac{e^{-\lambda t} (\lambda t)^k }{k!}

Where:

λ = Rate = 4 bites/hour and

t = Length of time that is

Mean = λt

Where k = 6 fishes bites and t = 2 hours we have

P(N(2) = 6) = \frac{e^{-4 \times 2} (4 \times 2)^6 }{6!} = 0.122

b) The probability that he fails to catch any fishes during the first two hours is the probability t that he catches 0 fish as follows

P(N(2) = 0) = \frac{e^{-4 \times 2} (4 \times 2)^0 }{0!} = 3.35 \times 10^{-4}

(c) Here we have

P(N(2) = 6) =  0.122

For 1 fish caught in two times we have first time no fish and second time he caches a fish gives

0.122×(1-0.122) = 0.1071

4 0
3 years ago
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