Which of these is the net of a cube?

Frank has been driving at a constant speed for 3 hours, during which time he traveled 195 miles. Frank would like to know how lo

anyanavicka [17]

So it takes him 3 hours to reach a distance of 195 miles. Divide that by 3 and we get 65 miles per hour. So we get the equation of 65h=195+455.
So 195+455= 650. H will be hours. So now we have 65h=650. Now divide 65 from 650 and we get 10=h So we need to find out how many more hours he has left. So it takes him 3 hours to reach 195 so if 10 hours=650 miles then, 10-3 hours=650-195 and we get 7 hours=455 miles.

4 0

4 years ago

Given ABCD is a parallelogram ABE equals 180° CBE is congruent to CEB prove DAE is congruent to CEA

katrin2010 [14]

Answer:

The proved is given below.

Step-by-step explanation:

Given ABCD is a parallelogram and also ∠ABE equals 180°, ∠CBE ≅ ∠CEB

We have to prove that ∠DAE ≅ ∠CEA

As ∠CEA=∠CBE → (1)

and given ABCD is a parallelogram implies AD||CB

∴ ∠DAE=∠CBE → (2) as these are corresponding angles.

From equation (1) and (2), we get

∠DAE=∠CEA

Hence, ∠DAE is congruent to ∠CEA

Hence Proved

6 0

3 years ago

You and your friend each deposit $50 in separate savings accounts. Your account earns 2% simple annual interest Your friend's ac

Vladimir [108]

Answer:

The answers are 20 years for myself and 10 years for your friend

Step-by-step explanation:

I need help on how to write the whole format out but those are definitely the right answers.

4 0

3 years ago

Sat question+if a right circular cylinder has a radius of 2 cm and a volume of 100π cubic cm, what is the height of the g in cen

asambeis [7]

The volume of a right circular cylinder is V=πr²*h
V=π*2*2*h=100π
h=25cm

7 0

4 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$