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dolphi86 [110]
4 years ago
8

The fourth term of an arithmetic

Mathematics
1 answer:
yulyashka [42]4 years ago
5 0

Answer:

2

Step-by-step explanation:

<u>Given AP where:</u>

  • a₄ = 2a₂ - 1
  • a₆ = 7

<u>To find</u>

  • a₁ = ?

<u>Since</u>

  • a₄ = a₁ + 3d
  • a₂ = a₁ + d
  • a₆ = a₁ + 5d

<u>Initial equations will change as:</u>

  • a₁ + 3d = 2(a₁ + d) - 1  ⇒  a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
  • a₁ + 5d = 7 ⇒ a₁ = 7 - 5d

<u>Comparing the above:</u>

  • d + 1 = 7 - 5d
  • 6d = 6
  • d = 1

<u>Then:</u>

  • a₁ = d + 1 = 1 + 1 = 2
  • a₁ = 2

The first term is 2

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3 years ago
Drag the similar figure into the table.
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'Similar' Figure(s):

1.) 4 and 2

2.) 10 and 4

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The credit purchase of a new oven for $5,900 was posted to Kitchen Equipment as a $5,900 debit and to Accounts Payable as a $5,9
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3 years ago
When the sum of a number and 3 is subtracted from 10 the result is 5 solve om algebraic equation?
german

Answer:

y = 2

Step-by-step explanation:

Algebraic Equation is an equation where alphabets are used to represent numbers.

Solving the above question,

Let the number = y

Therefore,

Sum of the number = y + 3

If it's subtracted from 10 it becomes

10 - ( y + 3 )

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- y = 5 - 10 + 3

- y = -2

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2 years ago
Find the point P on the line yequals=66x that is closest to the point (74 comma 0 )(74,0). What is the least distance between P
tekilochka [14]

Answer:

The point P that is closest to the point (74, 0) is P(7.4, 22.2), and the least distance between P and (74, 0) is 70.2

Step-by-step explanation:

Given

y = 66x

And a point A(74, 0)

We are required to find the point on the line that is closest to A, and then find the distance between these points.

Let the point be P(s, t)

Because it's coordinate satisfies the given equation

y = 3x

Let t = 3s, then we have

p(s, t) = P(s, 3s)

Next, we find the distance between P and A

Let the distance be

D = √[(x1 - y1)² + (x2 - y2)²]

Here x1 = 74, x2 = 0, y1 = s, y2 = 3s.

D = √[(74 - s)² + (0 - 3s)²]

= √(s² - 148s + 5476 + 9s²)

= √(10s² - 148s + 5479)

To maximize the distance, we find the derivative of D with respect to s, and set it to 0.

That is dD/ds = 0

dD/ds =

(20s - 148)/2√(10s² - 148s 5479) = 0

=> 20s - 148 = 0

20s = 148

s = 148/20

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Since t = 3s, we have

t = 22.2

So, the point is P(7.4, 22.2)

Finally, we find the distance D.

D = √[(74 - s)² + (0 - 3s)²]

D = √[(74 - 7.4)² + (0 - 3×7.4)²]

D = √(4435.56 + 492.84)

= √4928.4

D = 70.2

Therefore, the distance is 70.2

4 0
3 years ago
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