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Romashka-Z-Leto [24]
3 years ago
5

What is the constant in this algebraic expression? 7d+2 I need help

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0
It is 2 because no variable
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Plz Help Me
eduard

Answer:

0%

Step-by-step explanation:

They all liked one type of food.

6 0
3 years ago
Whats the slope intercept form for the points [5,2] and [0,-1]
Advocard [28]

Answer:

\displaystyle y=\frac{3}{5}x-1

Step-by-step explanation:

<u>The Equation of a Line</u>

The equation of the line in slope-intercept form is:

y=mx+b

Where m is the slope and b the y-intercept.

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

We are given the points (5,2) and (0,-1), thus:

\displaystyle y-2=\frac{-1-2}{0-5}(x-5)

Operating:

\displaystyle y-2=\frac{-3}{-5}(x-5)

\displaystyle y-2=\frac{3}{5}(x-5)

To find the slope-intercept form, we continue to simplify the expression:

Removing the parentheses:

\displaystyle y-2=\frac{3}{5}x-\frac{3}{5}\cdot 5

\displaystyle y-2=\frac{3}{5}x-3

Adding 2:

\displaystyle y=\frac{3}{5}x-3+2

\mathbf{\displaystyle y=\frac{3}{5}x-1}

4 0
3 years ago
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
Create a system of equations to solve
antiseptic1488 [7]
R=2K which equals 2R=4K
4(R=K+8) or 4R=4K+32

Subtract first equation from second equation.
2R=32 so R=16

Plug into first equation
16=2K so K=8

Now plug both into second equation to check
4R-4K=4(R-K)=4(8)=32 it works

So Roberto is 16 and Katie is 8
(In 4 years R would be 20 and K would be 12 which has a difference of 8)
6 0
3 years ago
A pelican starts at 60 feet above sea level. It descends 60 feet to catch a fish
Ksivusya [100]
Zero because 60 plus negative 60 equals 0
4 0
4 years ago
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