5⁰ = 1
5¹ = 5
5² = 25
5³ = 125
5⁴ = 625
5⁵ = 3125
Given:
The function is:

To find:
The roots of the given equation.
Solution:
We have,

For roots,
.




On further simplification, we get



Using zero product property, we get


Similarly,


And,


Therefore, the zeroes of the given function are
and the factor form of the given function is
.
The length of HI IS 3 since 9-6 is 3
1. (2r + 9)(2r-9) = 4r^2 -81
+ (2r - 9)^2 = 4r^2 - 36r + 81
= 8r^2 - 36r
2. 12 - 5 [ a^2 + a - 1 ] + 5a
= 12 - 5a^2 - 5a + 5 +5a
= 17 - 5a^2
x^3 + 3x^2 + 6x + 18
______
3. x-3/ x^4 + 7
- ( x^4 - 3x^3)
----------------
3x^3 + 7
- (3x^3 - 6x^2)
-------------------
6x^2 + 7
- (6x^2 - 18x)
-------------------
18x + 7
- (18x - 54)
--------------
7 + 54 = R = 61
welp That's What I get