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Thepotemich [5.8K]
4 years ago
11

The next number in the pattern 1 5 25 125 625

Mathematics
1 answer:
chubhunter [2.5K]4 years ago
5 0
5⁰ = 1
5¹ = 5
5² = 25
5³ = 125
5⁴ = 625
5⁵ = 3125
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Answer with A B C D. Correct answer gets brainlest.
Snowcat [4.5K]

Answer:

B

Step-by-step explanation:

The equation would be "42/n -8" That means the answer is B

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4 years ago
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At a hockey game a vendor sold a combine total of 248 sodas and hot dogs. The number of sodas sold was three times the number of
8_murik_8 [283]

Answer:

total =248

sodas=3x

hot dogs=x

3x+x=248

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3 years ago
What is the solution to the inequality below 8 m> 40
nalin [4]

Answer:

M>5

Step-by-step explanation:

Lets just rewrite the equation

8m>40 is the same as m(8)>40

lets divide

8m / 8>40/8

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4 0
3 years ago
We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance
MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

h(t) = -16\cdot t^{2}+256\cdot t+1680 (1)

Where:

h - Height above the ground, measured in feet.

t - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680

h(3\,s) = 2304\,ft

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at t = 5\,s and t = 7\,s:

h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680

h(5\,s) = 2560\,s

h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680

h(7\,s) = 2688\,s

We notice that the small object ascends in the given interval.

\Delta h = h(7\,s)-h(5\,s)

\Delta h = 128\,ft

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that h = 2640\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t-960=0 (2)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 10\,s and t_{2}= 6\,s

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that h = 0\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t +1680 = 0 (3)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 21\,s and t_{2} = -5\,s

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

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3 years ago
What expression is equivalent to -7(5a)
Aneli [31]

Answer:

-35a

Step-by-step explanation:

Here, you just distribute: -7 * 5a

= -35a

7 0
3 years ago
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