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Kryger [21]
3 years ago
14

8 \cdot 10^48⋅10 4 8, dot, 10, start superscript, 4, end superscript is how many times as large as 4\cdot10^{-5}4⋅10 −5 4, dot,

10, start superscript, minus, 5, end superscript?
Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

\bold{2\cdot10^9}

Step-by-step explanation:

The given expression s are:

8 \cdot 10^4 and

4\cdot10^{-5}

To find:

8 \cdot 10^4 is how many times  as large as 4\cdot10^{-5}.

Solution:

Let 8 \cdot 10^4 is x times as large as 4\cdot10^{-5}.

So, we can say that:

8 \cdot 10^4  = 4\cdot10^{-5}\times x

OR

x= \dfrac{8\cdot 10^4}{4\cdot 10^{-5}}

Let us have a look at the formula for exponents:

\dfrac{x^p}{x^q}   = x^{p-q}

Here we have:

x=10\\p=4\ and\\q=-5

Solving the expression using above formula:

\Rightarrow x= \dfrac{8}{4}\cdot 10^{4-(-5)}} = \bold{2\cdot10^9}

So, Let 8 \cdot 10^4 is \bold{2\cdot10^9} times as large as 4\cdot10^{-5}

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