Ask question

Ask question

All categories

3 years ago

11

Please help me....I really need help!!

1 answer:

scoundrel [369]3 years ago

6 0

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

You might be interested in

The Drombeg stone circle is a collection of megaliths (large prehistoric stones) located in Glandore, Ireland, that was used bet

disa [49]

Answer:

A

Step-by-step explanation:

A is the reasonable answer

4 0

2 years ago

Read 2 more answers

If Kamila can do a job in 26 hours and Simon and Kamila working together can do the same job in 9 hours , find how long it takes

Kay [80]

Answer:

Simon takes approximately 13.76 hours to complete the job alone.

Step-by-step explanation:

We are given the following in the question:

Kamila can do a job in 26 hours

So, part of work done by Kamila in 1 hour =

$\dfrac{1}{26}$

Simon and Kamila working together can do the same job in 9 hours .

So, (Simon and Kamila)'s 1 hour work =

$\dfrac{1}{9}$

So, Simon's 1 hour work =

$\dfrac{1}{9}-\dfrac{1}{26}=\dfrac{17}{234}$

So,

Simon can do $\frac{17}{234}$ part of work in hour = 1

Time taken by Simon to complete the job alone =

$\dfrac{1}{\frac{17}{234}}=\dfrac{234}{17}\approx 13.76 \text{ hours}$

Thus, Simon takes approximately 13.76 hours to complete the job alone.

3 0

2 years ago

15/3 = 5 4_7 + 5 2_3<br> b=?

OLEGan [10]

Answer:

válla si son brutos está bien fácil esa pregunta lo que pasa es que estoy haciendo mi trabajo

5 0

2 years ago

Read 2 more answers

What equals 12.5 in multiplication

kramer

2 x 6.25
is equal to 12.5 in multiplication

7 0

3 years ago

Please i need to know if im correct with these questions

telo118 [61]

Answer: No Solution

<u>Step-by-step explanation:</u>

ln x - ln (x + 2) = 4 restrictions: x > 0 and x + 2 > 0 → x > 0

ln $(\frac{x}{x + 2})$ = 4

$(\frac{x}{x + 2})$ = e⁴

x = e⁴ (x + 2)

x = 54.5982 (x + 2)

x = 54.5982x + 109.1964

- 53.5982x = 109.1964

x = $\frac{109.1964}{-53.5982}$

x = -2.0373

-2.0373 is not greater than 0 so is not valid

**************************************************************************

Answer: 2.1972

<u>Step-by-step explanation:</u>

eˣ = 9

ln eˣ = ln 9

x = ln 9

x ≈ 2.1972

**************************************************************************

Answer: $\frac{3}{2}$

<u>Step-by-step explanation:</u>

log₂ (3x - 4) = -1

3x - 4 = 2⁻¹

3x - 4 = $\frac{1}{2}$

<u> +4 </u> <u>+4 </u>

3x = $4\frac{1}{2}$

3x = $\frac{9}{2}$

$\frac{3x}{3} = \frac{9}{2} * \frac{1}{3}$

x = $\frac{3}{2}$

**************************************************************************

Answer: 1.117519

<u>Step-by-step explanation:</u>

in the calculator, type in 1 ÷ 9.

Then hit the eˣ button.

e¹⁾⁹

= e°¹¹¹¹¹¹

= 1.117519

rounded to 6 decimal places: 1.117519

6 0

2 years ago