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Licemer1 [7]
3 years ago
6

Compare and contrast the expression 2+x and 2+3

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0
So first, just simply solve both and then it become obvious. The expression 3-(2+5), you can evaluate what's inside the parentheses first and then your answer will be in the form of a integer: 3-(2+5) = 3-7 = -4 With the second one, your answer will be in the form of a simplified expression because we don't know what x is: 3x-(2x+5) = 3x-2x-5 = x - 5 Also, in the second one, you have to expand the parentheses in order to simplify it.
NikAS [45]3 years ago
4 0
Well the first equation has a variable in it while the other one doesn't also the first expression if set equal to 0 is -2 while the other one is 5
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Step-by-step explanation:

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I BEG YOU I WILL DO ANYTHING HELP algebraically solve the following system of equations. Show all your work
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<h2>Answers:</h2>

  • Solving for x on the question - <em>2x + 3y = 32</em>  |  
  1. Answer : x =  \frac{-3}{2}⁻y + 16

  • Solving for y on the question - <em>2x + 3y = 32</em>  |  
  1. Answer : y = \frac{-2}{3}x + \frac{32}{3}
<h3></h3>
  • Solving for x on question - 5x - 4y = -81 |
  1. Answer : x =  \frac{4}{5}y + \frac{-81}{5}

  • Solving for y on question - 5x - 4y = -81 |
  1. Answer : y =  \frac{-5}{4}x + \frac{81}{4}
<h2>Step-by-step explanation:</h2>

<em>(Solving for x on question - 2x + 3y = 32)</em>

2x + 3y = 32

Step 1: Add -3y to both sides.

2x + 3y + −3y = 32 + −3y

2x = −3y + 32

Step 2: Divide both sides by 2.

\frac{2x}{2}  = \frac{-3y+32}{2}

<u>x =  </u>\frac{-3}{2}<u>⁻y + 16</u><u>                                                                                                                 </u>

<em>(Solving for y on question - 2x + 3y = 32)</em>

2x + 3y = 32

Step 1: Add -2x to both sides.

2x + 3y + −2x = 32+ −2x

3y = −2x + 32

Step 2: Divide both sides by 3.

\frac{3y}{3} =  \frac{-2x+32}{3}

<u>y = </u>\frac{-2}{3}<u>x + </u>\frac{32}{3}<u>                                                                                                           </u>

<em>(Solving for x on question - 5x - 4y = -81)</em>

5x − 4y = −81

Step 1: Add 4y to both sides.

5x − 4y + 4y = −81 + 4y

5x = 4y − 81

Step 2: Divide both sides by 5.

\frac{5x}{5} =  \frac{4y-81}{5}

<u>x =  </u>\frac{4}{5}<u>y + </u>\frac{-81}{5}<u>                                                                                                               </u>

<em>(Solving for y on question - 5x - 4y = -81 )</em>

5x − 4y = −81

Step 1: Add -5x to both sides.

5x − 4y + −5x = −81 + −5x

−4y = −5x − 81

Step 2: Divide both sides by -4.

\frac{-4y}{-4} = \frac{-5x-81}{-4}

y =  \frac{-5}{4}x + \frac{81}{4}

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