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levacccp [35]
4 years ago
15

Help !!! Please !!!!!!

Mathematics
1 answer:
mylen [45]4 years ago
6 0
I think that the answer is a hoped i helped
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Wil paid $35 for 5 T-shirts. Some of the T-shirts cost $5 each and the rest coast $10 each. Write and solve a system of equation
lawyer [7]
X is shirt type 1, y is shirt type 2

x+y=5
<span>
5x+10y=35

</span>Use elimination.
solve for y
plug in y in one of the equations to find x 


4 0
3 years ago
The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the nu
vampirchik [111]

ANSWER

4,8,14

EXPLANATION

Let the first number be

x

Then the second number will be

2x

and the third number is

2x + 6

The sum of these numbers is 26.

This implies that;

x + 2x + (2x + 6) = 26

Group similar terms;

x + 2x + 2x = 26 - 6

Simplify;

5x = 20

Divide both sides by 5

x =  \frac{20}{5}

This gives us;

x = 4

The numbers are:

4,8,14

3 0
3 years ago
You spin the spinner and flip a coin. Find the probability of the compound event. The probability of spinning a prime number and
elixir [45]
The probability of spinning a prime number and not flipping heads will be given as follows:
P(Prime)*P(Tails)
P(Prime)=3/5
P(Tails)=1/2
Thus
P(Prime) and P(Tails)
=3/5×1/2
=3/10
3 0
4 years ago
Read 2 more answers
Find the 65th term of a arithmetic sequence -10,-8,-6,-4......
Masja [62]
-69 is the answer i think
8 0
3 years ago
Write the following in terms of sin θ and cos θ; then simplify if possible. (Leave your answer in terms of sin θ and/or cos θ.)
erma4kov [3.2K]

Answer: 1/cos θ

Step-by-step explanation:

From basic trigonometry, csc θ is the short form of cosec θ which is further expressed as

csc θ = 1/sin θ

Also,

tan θ = sin θ/cos θ

Knowing this basis of trigonometry makes the simplification easy for us.

Firstly, expressing the equation in terms of sin θ and cos θ,

The equation becomes csc θ * tan θ = [1/sin θ] * [sin θ/ cos θ]

Further simplifying by multiplication, our answer becomes

1/cos θ

6 0
3 years ago
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