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3 years ago

12

How do you write 39/10 as a percentage?

2 answers:

g100num [7]3 years ago

7 0

39/10
= (39*10) / (10*10)
= 390/ 100
= 390%

The final answer is 390%~

solmaris [256]3 years ago

4 0

Answer:
39/10

39 ÷ 10= 3.9

<span>3.9 x 100 = 390%</span>

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Use synthetic division to find (x^2+3x–4)÷(x+4)

Jobisdone [24]

Answer:

X^2-x- 8/x+4

Step-by-step explanation:

X+4 becomes a negative 4

Then multiply -4 by the first number which is 1 so -4×1 is -4. Then subtract -4 by the second number 3. This gives you -1 so multiply that by 4 which is -4. Then subtract 4 from the third number -4. So that'll give you -8. Then add an x-value to every number except the very last number as that number will be you remainder.

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3 years ago

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Which of these is a simplified form of the equation 7y + 8 = 9 + 3y + 2y? 7y = 6 5y = 17 12y = 17 2y = 1

LekaFEV [45]

7y +8= 9+3y+2y

Combine like terms.

7y+8= 9+5y

Subtract 5y on both sides.

2y+8=9

Subtract 8 on both sides.

2y=1

Your answer is 2y=1

I hope this helps!
~kaikers

4 0

3 years ago

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Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

Add 5 over 3 + 2 over 4 =

Leokris [45]

Answer:

exact form: 13 over 6

decimal form: 2.16

mixed number form: 2/ 1 over 6

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3 years ago

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A shop keeper has 8 gallons, 3 quarts,

ioda

Answer:

I believe it would be 86 cups left of milk.

Step-by-step explanation:

8 gallons= 128 cups of milk

3 quarts= 12 cups

Plus the 1 cup of milk he had equals 141 of milk in total

Now the customer wants 2 gallons (32 cups of milk), 5 quarts ( 20 cups), and 3 cups which is 55 cups of milk.

Now we minus what the customer bought from what the shop keeper had so:

55-141=86

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3 years ago