By testing the hypothesis we can conclude that the bag does not contain 11 kg of food.
Given mean of 10.6 kg, population standard deviation of 0.6 and sample size of 25.
We are required to find whether the company is right in saying that their bags contain 11 kg of food.
First we have to make hypothesis.
:μ≠11
:μ=11
We have to use t statistic because the sample size is less than 30.
t=(X-μ)/s/
We will use s/=0.6 because we have already given population standard deviation of weights.
t=(11-10.6)/0.6
=0.4/0.6
=0.667
Degree of freedom=n-1
=25-1
=24
T critical at 0.05 with degree of freedom 24=2.0639
T critical at 0.05 with degree of freedom is greater than calculated t so we will accept the null hypothesis.It concludes that the bags donot contain 11 kg of food.
Hence by testing the hypothesis we can conclude that the bag does not contain 11 kg of food.
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Answer:
(42, 21) or (–42, –21)
Step-by-step explanation:
let A(x, y), A on line 2y = x
distance
x² + y² = 2205
(2y)² + y² = 2205
y² = 441
y = ±21
x = ±42
Answer: The height of the kite above the point at which the string is held is 
feet.
Step-by-step explanation:
Given : A kite is being flown at 
. The string of the kite is 120 feet long.
Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.
Now, in right Δ ABC
hence, The height of the kite above the point at which the string is held is feet.
Your Answer is <span>15x^3y^4z^3</span>
Answer: 24
Step-by-step explanation:
Amount of bushels of peas collected = 42
Fraction that'll be sent to market = 3/7
Fraction that'll be kept = 1 - 3/7 = 7/7 - 3/7 = 4/7
The number of bushels that'll be kept will be:
= Fraction that'll be kept × Total number of bushels collected
= 4/7 × 42
= 24
