Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
= Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).
I don’t know if you need to round, but you can do so on the answer for mondays if necessary
On Monday, the animals cost $1.03125.
On Tuesday, the animals cost exactly $1.
The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2
<u>Solution:</u>
Given that line is passing through point (-5, 2) and (3, r)
Slope of the line is 
Need to determine value of r.
Slope of a line passing through point 
is given by following formula:
--- eqn 1
On substituting the given value in (1) we get
Hence the value of "r" is -2
Answer:
-14
Step-by-step explanation:
Multiply the is together. Multiply the j's together. Add the answer. The answer is a scalar.
(7 × -2) + (5 × 0)
= -14
Answer:
y = 2|x+3| -2
Step-by-step explanation:
1) slope = rise/run= 4/2 =2 - for the right line
2) y = 2|x| initial graph
3) It is moved 3 units left
y = 2|x+3|
4) It moved 2 units down
y = 2|x+3| -2
