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Arlecino [84]
3 years ago
13

How much money, invested at an interest rate of r % per year compounded continuously, will amount to A dollars after t years? (R

ound your answer to the nearest cent.)
A = 17,000, r = 4.3, t = 3
Mathematics
1 answer:
Talja [164]3 years ago
6 0
A=A(1+r/100)^t
a=17000(1+.043)^3
a=19.288.65
a is your money after 3 years
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When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?
vovangra [49]

Answer:

Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

Step-by-step explanation:

We need to simplify the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

First we will solve terms inside the bracket

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

Converting mixed fraction 1\frac{1}{2} y into improper fraction, we get: \frac{3}{2}y

Replacing the term:

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)

Now, combine like terms

2(36x-15x-90y+40y-180)\\2(21x-50y-180)

Now, multiply all terms with 2

42x-100y-360

So, Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

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Answer:

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