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3 years ago

X to the 3rd power equals 343 what is x

Mathematics

2 answers:

Anon25 [30]3 years ago

6 0

7 times 7 = 49
49 times 7 = 343
x = 7

Minchanka [31]3 years ago

4 0

Your answers is
x equals 7

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Sonbull [250]

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2 years ago

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Evaluate 0.3y + y/x when y = 10 and z =5

coldgirl [10]

Answer:

Step-by-step explanation:

0.3*10=3

10/5=2

--------------------

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3 years ago

If x represents an even number, which expression represents an odd number?

Sauron [17]

Test the choices !
Pick an even number, and see what each choice does to it.

Let's start with, say, 6 .
We'll try each choice, and see which one produces an odd number:

a). 6 to the 2nd power. . . . . . 6 x 6 = 36. That's not an odd number.

b). 6 + 3 = 9 This could be it. 9 is odd. We'll save this one.

c). 3·6 = 18. That's not an odd number.

d). 6/3 = 2. That's not an odd number.

The only one that gave us an odd number is (b).

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3 years ago

Re-write the equation after you distribute and combine all the like terms. 12-4(-3x+5)-8x=20

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3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago