The measure of an angle is 52 more than its complement. what is the measure of the angle

If a b c=0, but abc don't equal 0, then a^2/bc b^2/ca c^2/ab=

goblinko [34]

$\sf a + b + c = 0\\abc \neq 0\\\\ \frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = \frac{a^3+b^3+c^3}{abc} \\\\\sf Formula: \\a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc\\\\\frac{a^3+b^3+c^3}{abc}= \frac{(a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf However, ~a+b+c = 0. ~So:\\\\\frac{0 (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf Multiply~ anything ~by~ 0, ~and~ you ~get~ 0. ~So~ simplifying:\\\\\frac{3abc}{abc} = \boxed{3}$

Your final answer is 3.

3 0

3 years ago

Melissa collected 14 bottles on Saturday and 9 bottles on sunday for recycling. on monday, she took all the bottles to the recyc

lina2011 [118]

Answer:

Option B is correct that is the amount she is getting per bottle is $0.15

Step-by-step explanation:

We have been given the information that Melisande collected 14 bottles on Saturday and 9 bottles on Sunday

That means she has collected a total of 23 bottles

Let us assume that the amount she is paid for recycling is $b

Since she is left with $3.20 after the amount she gets for bottles we will get the equation below:

23b=3.20

Now, since she has to pay a one-time service fee equation will become

23b -0.25 =3.20

After simplification, we will get

23b=3.20+0.25=3.45

b=3.45/23=.15

b=$0.15

Therefore, The amount she is getting per bottle is $0.15

HOPE THIS HELPS :)

5 0

4 years ago

Read 2 more answers

18+

OLga [1]

Answer:

I will answer this for you if you put this into understandable terms.

4 0

3 years ago

Find the slope of the line that passes through the

Lana71 [14]

Answer:

The slope of the line that passes through the points is 0 slope. That is B is the answer.

7 0

3 years ago

Most people complain that they gain weight during the December holidays. To find out how much, we sample the weights of 23 adult

kakasveta [241]

Answer:

The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 23 - 1 = 22

88% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.88}{2} = 0.94$ . So we have T = 1.6176

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.6176\frac{8.73}{\sqrt{23}} = 2.94$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.64 - 2.94 = -1.30 lbs

The upper end of the interval is the sample mean added to M. So it is 1.64 + 2.94 = 4.58 lbs

The 88% confidence level for the average weight gain if between -1.30 lbs and 4.58 lbs.

5 0

3 years ago