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ycow [4]
3 years ago
15

cassie draws 1 line to cut a square into two smaller shapes. which could NOT be the two smaller shapes?

Mathematics
2 answers:
lilavasa [31]3 years ago
8 0
Trapezoids because no matter what way you place them it can not make a square
rosijanka [135]3 years ago
3 0
They could ONLY be triangles, rectangles, or nameless quadrilaterals. They couldn't be anything else.
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a piece of wire 17m long stretched from the top a flagpole to point p on the ground if p is8m from the pole how tall is the pole
lakkis [162]

Answer:

Step-by-step explanation:

By the Pythagorean Theorem

17^2=8^2+h^2

h^2=17^2-8^2

h^2=289-64

h^2=225

h=15 meters

6 0
3 years ago
Help please my mother took my phone so i can't get help from discord
siniylev [52]

The answer is 2n - 1 = 12

Hope that helps!

7 0
3 years ago
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(15) Geometry Help plz
MakcuM [25]
X = measure of angle 1
y = measure of angle 2
z = measure of angle 3
w = measure of angle 4

Focus on the bottom triangle. The three angles add to 180 degrees
(angle 2) + (angle 3) + 116 = 180
y+z+116 = 180
y+z= 180-116
y+z= 64

Since we have the bottom triangle as isosceles, this means that y = z, so
y+z = 64
y+y = 64
2y = 64
y = 64/2
y = 32
making z = 32 as well

Similarly, angle 1 and angle 4 are 32 degrees because the 116 angle is opposite the top left-most angle, and congruent to this angle. In other words, the bottom triangle is a mirror image of the top triangle.

The figure is a rhombus because all four sides are the same length (as shown by the tickmarks)

-----------------------------------------------------------

Answer: 
This figure is a rhombus
All four angles (angle 1 through angle 4) are the same measure. They are each 32 degrees

6 0
4 years ago
Plz answer thanks asap need it really bad
Kisachek [45]
I believe its C

Hoped I help :)

And have a nice day/weekend :)
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3 0
4 years ago
Read 2 more answers
A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the
Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of​ metal

y ----> the original width of the piece of​ metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in

The volume of the box is equal to

V=(x-10)(y-10)5

V=930\ in^3

so

930=(x-10)(y-10)5

simplify

186=(x-10)(y-10) -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

x=y+25 ----> equation B

substitute equation B in equation A

186=(y+25-10)(y-10)

solve for y

186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

x=16+25=41

therefore

The original length was 41 inches and the original width was 16 inches

3 0
3 years ago
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