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Anna11 [10]
3 years ago
10

The Wagner school store is having a sale! At the sale this week, a life sized stuffed animal of Wagner’s mascot is being sold fo

r $158.40. This is a 52% discount of the original price. What is the original price? If necessary, round to the nearest cent.
Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

LOL

Step-by-step explanation:

You might be interested in
Elena surveyed her classmates to see how many like to make jewelry. When she asked 20 of her classmates, 50 percent said they li
nordsb [41]

10 students of Elena's classmates like to make jewellery.

<u>Step-by-step explanation:</u>

Let total no.of classmates who liked the jewellery = x

Here, in the given problem, given she asked her classmates '20'. So, it clearly shows that total number of students/classmates = 20. Also, in that, 50% said like to make jewellery. Now find 'x' as below,

                    x = 50 \% \text { of } 20

                    x = \frac{50}{100} \times 20

                    x = 10

Hence, the total number of classmates who liked to make Jewellery = 10

5 0
3 years ago
How many liters of pure water should be mixed with 18 liters of a12% saline solution to make a saline solution that is 3% salt?
Volgvan

Answer: .42857 liters of pure water


Step-by-step explanation:2.4 = .7w + 2.1

2.4 - 2.1 = .7w

.3 = .7w

w = .3%2F.7


3 0
3 years ago
If f(x) = (-x)^3, what is f(-2)?<br> -6<br> -8<br> 8<br> 6
lys-0071 [83]

Answer:

The answer is 8

Step-by-step explanation:

Plug -2 in for x. The double-negative inside the parenthesis makes it positive, then do the exponent.

6 0
3 years ago
Read 2 more answers
If t follows a t7 distribution, find t0 such that (a) p(|t | &lt; t0) = .9 and (b) p(t &gt; t0) = .05.
Thepotemich [5.8K]

Answer:

a) P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

b) For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For this case we know that t \sim t(df=7)

And we want to find:

Part a

P(|t|

We can rewrite the expression using properties for the absolute value like this:

P(-t_o < t_7

Using the symmetrical property we can write this like this:

1-2P(t_7

We can solve for the probability like this:

2P(t_7

P(t_7

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be t_o =\pm 1.895

Part b

P(t>t_o) =0.05

For this case we can use the complement rule and we got:

1-P(t_7

We can solve for the probability and we got:

P(t_7

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be t_o = 1.895

5 0
3 years ago
In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each even
murzikaleks [220]

The figure depicting the board game is attached below.

Answer:

Step-by-step explanation:

Kindly note that selections done without replacement.

Count of numbers on the board game = 8

Count of odd numbers = (1, 9, 1) = 3

Count of digit 6 = 3

Probability = required outcome / Total possible outcomes

P(picking an odd number) = 3 / 8

Without replacement

Numbers left on board game = 8 - 1 = 7

P(picking a 6) = 3 / 7

Hence,

P(picking an odd number then, a 6) = 3/8 * 3/7 = 9 / 56

7 0
3 years ago
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